Question

a bullet leaves the barrel of a gun with a velocity of 60 metre per second if the barrel of the gun is 150 cm long find the average acceleration of the bullet inside barrel​

Answer 1

Answer: average acceleration of the bullet inside barrel​ is  1200 m/$s^{2}$ .

Explanation:

Given velocity , v=60m/s

initial velocity , u=0m/s

Length of barrel ,s=150cm=1.5m

Therefore average velocity

Vav = $\frac{v+u}{2}$ = $\frac{60+0}{2}$ = 30 m/s

& from equation of motion ,we have

$V^{2}$ = $V^{2}$ + 2as

Acceleration, a = $\frac{v^{2}-u^{2} }{2s}$

                          = $\frac{60^{2} }{2 X 1.5}$

                          =  1200 m/$s^{2}$

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