a bullet leaves the barrel of a rifle with a speed of 300 M per second if the length of the barrel is 0.9 M at what rate is the bullet accelerated while in the barrel
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0
In about 0.003 seconds.
abhishekanand2378:
5×10 to the power 4
Answered by
2
We can use the formula:
vf^2 - vo^2 = 2ad
where
vf = final velocity
vo = initial velocity
a = acceleration
d = distance
Substituting,
300^2 - 0^2 = 2(a)(0.9)
a =632 m/s^2
vf^2 - vo^2 = 2ad
where
vf = final velocity
vo = initial velocity
a = acceleration
d = distance
Substituting,
300^2 - 0^2 = 2(a)(0.9)
a =632 m/s^2
ans-5×10to the power4 m/s square
your answer is wrong
if u dont know the solution, dont solve
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