A bullet leaves the barrel of a rifle with a speed of 300m/s. If the length of the barrel is 0.9m, at what rate is the bullet accelerated while in the barrel
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the correct answer is 50000m/s2
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Given:
The speed of bullet v=300 m/sec
The initial speed u=0
The length be s=0.9 m
To find:
The acceleration of the bullet.
Solution:
Using the formula of equation of motion.
v² - u²=2as
Putting the values.
(300)²-0=2×a×(0.9)
90000=1.8a
a=50000 m/sec²
So the acceleration of the bullet be a= 50000 m/sec²
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