a bullet leaves the nozzle of the gun with velocity of 750m/s. assume constant acceleration from the breech to nozzle. find the time occupied by the bullet in traveling through the gun barrel which is 0.75m long
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Answered by
5
Answer:
Velocity=Displacement/Time
750=0.75/Time
therefore, Time=0.75/750
=0.001 s
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Answered by
21
v^2 - u^2 = 2aS
750*750 = 2*a*0.75
a = 375000 m/s^2
v = u+ at
750 = 0+ 375000*t
t = 2ms
Explanation:
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