Question

A bullet mass 0.008kg is fired with the velocity of 80m/s calculate the kinetic energy

Answer 1

Answer:

K.E. = 1/2mv²

K.E. = 1/2 × 0.008× 80 × 80

K.E. = 1×8×80×80/2×1000

K.E. = 8×8×8/20

K.E. = 128/5 = 25.6

Answer 2

Answer:

A bullet of mass 0.008kg is fired with a velocity of 80m/s, the kinetic energy of the bullet is 25.6J

Explanation:

• Kinetic energy is the energy of a moving body

• for a body of mass (m) moving with velocity (v) kinetic energy is given by the formula

               $KE=\frac{1}{2} mv^{2}$

From the question, it is given that

mass of the bullet $m=0.008kg$

the velocity of the bullet $v=80m/s$

therefore kinetic energy of the bullet,

$KE=\frac{1}{2}*0.008*80*80=25.6J$