a bullet moving at 20m/s it strikes a wooden plank and penetrates 4cm before coming to stop the time taken to stop is
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from 3rd equation of newton
v² - u² = 2aS
= 0 - 20² = 2×a×0.04
= -400 = 0.08a
= a = -400/0.08
= a = -5000 m/s²
now we take 1st equation of newton
v = u + at
= 0 = 20 + (-5000)×t
= -5000t + 20 = 0
= -5000t = -20
= t = 20 / 5000
= t = 0.004 sec.
i hope it will help you
regards
v² - u² = 2aS
= 0 - 20² = 2×a×0.04
= -400 = 0.08a
= a = -400/0.08
= a = -5000 m/s²
now we take 1st equation of newton
v = u + at
= 0 = 20 + (-5000)×t
= -5000t + 20 = 0
= -5000t = -20
= t = 20 / 5000
= t = 0.004 sec.
i hope it will help you
regards
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