Question

A bullet moving at 250 m/s penetrates 5cm into a tree limb before coming to rest . Assuming that the force exerted by the limb is uniform, find its magnitude. Mass of the bullet is 10g? Answer this fast and clearly. Thank you.

Answer 1

hello friend..!!

⇒ according to the given question,

⇒  V = 250 m/s  and S = 5 cm ( distance penetrated  into the tree ) , M =10 g 

now, we should find the magnitude of force, 

⇒ we know that F = MA ----------(1)

now to find acceleration , 

⇒ v² - u²  = 2as 

⇒ a = ( v² - u² ) / 2s 

⇒ a = ( 0 - 250 ²) / 2 ( 0.05 )  { s = 5cm = 0.05 m }

⇒ a = 62500 / 0.1

⇒ a = 625000 ----------(2)

now by substituting equation (2) in (1) gives ,

F = M ( 625000)

from the given we know that M = 10 g = 0.01 Kg 

therefore , F = 0.01( 625000)

⇒ F = 6250 N .

therefore the magnitude of force is 6250 N . 

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hope it is useful..!!

Answer 2

Answer:

regarding force=?

v²=u²+2as

0²=250²+2×a5×10-²

a=-250²/10-¹

a=-625000m/s²

retarding force=mass×retardation

=10-²×625000

=6250N

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