Question

a bullet moving at 500 m/s has a kinetic energy of 2500 J and a potential energy of 0.50 J at a certain moment. What is the bullet's mass and how high above the ground is it at that moment?

Answer 1

Answer:

Mass of bullet is 0.02 kg and height is 2.5 m

Explanation:

KE=2500J

v=500m/s

PE=0.50J

KE=1/2 mv²

2500=1/2×m×500×500

m=2500×2/500×500

m=0.02kg

Let gravity 10N

PE=mgh

0.50=0.02×10×h

h=0.50/0.02×10

h=2.5m

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