A bullet moving at 900 kmph penetrates 0.1 m into a tree before it stops. If the force exerted by the tree is uniform and if the mass of the bullet is 10 g , then the force exerted by the bullet on the tree is ?
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Answer:
Given,
m=10g=0.01kg
u=250m/s
s=5cm=0.05m
v=0m/s
3rd equation of motion,
v
2
−u
2
=2as
0
2
−(250)
2
=2×0.05×a
a=
0.1
62500
=−625000m/s
2
The magnitude of force exterted by the tree limb is,
F=ma
F=0.01×625000=6250N
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