Question

A bullet moving at 900 kmph penetrates 0.1 m into a tree before it stops. If the force exerted by the tree is uniform and if the mass of the bullet is 10 g , then the force exerted by the bullet on the tree is ?

Answer 1

Answer:

Given,

m=10g=0.01kg

u=250m/s

s=5cm=0.05m

v=0m/s

3rd equation of motion,

v

2

−u

2

=2as

0

2

−(250)

2

=2×0.05×a

a=

0.1

62500

=−625000m/s

2

The magnitude of force exterted by the tree limb is,

F=ma

F=0.01×625000=6250N