Question

a bullet moving horizontally with speed u strikes a vertically suspended Bob of same mass and emerges with 80 percentage of initial Speed the maximum height attained by the bob is 20 metre then u equal to (assume there is no loss of Mass)

Answer 1

You have to use Conservation of Momentum here,

Let ,

mv = (m+M) V

where V is a velocity of block and bullet combined after hit.

Now, when Block rises up the kinetic energy of block converted into potential energy.

so,

1/2 (m+M) V^2 = (m+M)gh

V^2 = 2gh

V = √2gh

so, we get

v = ( (m+M) ×√2gh) / m

if this help you then please give thanks and Mark brainliest

Answer 2

Explanation:

Q.1)a bullet moving horizontally with speed u strikes a vertically suspended Bob of same mass and emerges with 80 percentage of initial Speed the maximum height attained by the bob is 20 metre then u equal to (assume there is no loss of Mass)

ANSWER.)

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