Question

A bullet moving with 20m/s strikes a target and comes to rest after penetrating 10cm. Calculate the retardation.

Answer 1

Solution:-
Final velocity=0
Initial Velocity=20m/s
Time =10cm=1/10m

By using equation:-
$= > {v}^{2} = {u}^{2} + 2as \\ = > a = \frac{( {v}^{2} - {u}^{2}) }{2 \times s }$
$= > a = \frac{0 - 400}{2 \times \frac{1}{10} }$
$= > a = \frac{ - 400 \times 10}{2} \\ = > a = - 2000$
So,
Acceleration= -2000m/s^2
Retardation=2000m/s^2