Question

A bullet moving with a velocity 200 cm/s penetrates a wooden block and comes to rest after traversing 4 cm inside it.. What velocity is needed for traveling a distance at 9 cm in same block

Answer 1

$ASSALAMUALAIKUM$

GIVEN VALUES:-

intital velocity = 200m/s ; final velocity = ?
s= 4cm

SOLUTION:-

using third equation of motion-

v^= u^ +2as

0 = (200^) + 2*a*4

a = -5000 cm/s^

and now bullet travels S = 9cm

then,

v^= u^ +2as

0^= u^+ 2 (-5000)*9

after solving,

$u = 300 cm/s$

$INSHAALLAH it will help you!$

Answer 2

HEYA HERE IS UR ANSWER✌✌✌✌❤❤

IF U R FROM KASHMIR SO PLX REPLY

V=0 ; u=200 cm/sec ; distance =s=4 cm
From the third equation of motion:
V^2-u^2= 2as
0-(200)^2=2a.4
40000=8a
a=5000cm/sec^2
To travel 9 cm in a wooden block:
U=0;distance =9 cm
From the third equation of motion
V^2-u^2=2as
V^2-0=2×5000×9
V=300cm/sec
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