A bullet moving with a velocity of 20 m/sec hits a sand bag and comes to rest after penetrating 5 cm into the bag, then the retardation offered by the sand bag will be?
PLEASE ANSWER IT'A AN EMERGENCY.
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Explanation:
The deceleration is defined as the negative acceleration exerted by the body to come to rest from motion. As the bullet hits a sand box with velocity 20 m/s, it becomes the initial velocity exerted by the bullet and thus it covers a distance of 6 cm in the sand box with this velocity.
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Answer:
Answer is 4000m/S2
If you need full explanation
convert 5 cm into m
And using formula V2 =U2 + 2as
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