Physics, asked by S00819amanda, 1 month ago

A bullet moving with a velocity of 20 m/sec hits a sand bag and comes to rest after penetrating 5 cm into the bag, then the retardation offered by the sand bag will be?

PLEASE ANSWER IT'A AN EMERGENCY.

Answers

Answered by bluequeen25
1

Explanation:

The deceleration is defined as the negative acceleration exerted by the body to come to rest from motion. As the bullet hits a sand box with velocity 20 m/s, it becomes the initial velocity exerted by the bullet and thus it covers a distance of 6 cm in the sand box with this velocity.

Answered by khushipal99
1

Answer:

Answer is 4000m/S2

If you need full explanation

convert 5 cm into m

And using formula V2 =U2 + 2as

how it's helpful

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