A bullet moving with a velocity of 200 m per second penetrates a wooden block and comes to rest after travelling for centimetres inside it what velocity is needed for travelling distance of 9 cm in same block
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Dear Student,
Given Velocity = 200 cm/sec
Initial velocity = 0
From the Netwon's third Law of equation
V^2- U^2 = 2as
40000 = 8 a
a = 5000 cm/sec^2
v^2 = 40000+ 90000
V^2 = 130000
V = 100√13 cm/sec
This would be the velocity.
Cheers!!
Regards,
AJay
(B.tech second year, IIT(BHU)VARANASI )
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