Question

A bullet moving with a velocity of 300
m/sec. Strikes a tree and stops after
penetrating 10 cm. Find the retardation
of the bullet​

Answer 1

Answer:

Explanation:

initial velocity=300m sec^-1[u]

distance=0.1m[s]

final veocity=0m sec^-1[comes to rest][v]

we know,

v^2-u^2=2as

0-9*10^4=2*a*0.1

a= -4.5*10^5msec^-2

HOPE IT HELPS.