Question

A bullet moving with velocity 100 m/s penetrates
through a wooden block and emerges from the block
with velocity 10 m/s. If the width of the block is halved,
what would be the velocity of bullet after emerging from
the block?​

Answer 1

Answer:

244.9cm/s

v

2

−u

2

=2as

0−(200)

2

=2a×4

⇒a=5000cm/s

2

Now initial velocity to travel 6 cm,

0−u

2

=−2×5000×6

⇒u=244.9cm/s

Explanation:

hope you help it plz mark as brilliant

Answer 2

Answer:

$v=71.1m/s$

Explanation:

Using the third equation of motion, $v^{2} = u^2 + 2aS$

$v = 10m / s, u = 100m/s$

Let $t = 1 s, a= 90m/s^{2}$ and put solved $S=55m$ and again halved $s=\frac{55}{2}m$

and put solved $v = 71.1m/s$