Science, asked by udayarahul2158, 7 months ago

A bullet of 10 g strikes a sand bag at a speed of 103 m/s and gets embedded after travelling 5 cm.

Calculate (i) the resistive force exerted by the sand on the bullet.​

Answers

Answered by Itzsizllingritika01
2

Explanation:

A bullet of 10 g strikes a sand bag at a speed of 103 m/s and gets embedded after travelling 5 cm.

Calculate (i) the resistive force exerted by the sand on the bullet.

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Answered by aryantheboss69
1

mass of bullet should be =10gm=0.01kg initial velocity (U)of bullet=1000m/s final velocity (V)-0m/s(because it has stopped after striking sand) displacement of bullet=5cm-0.05m a)using 2as=V 212

2(a)(0.05)=02-100022a(5/100)=-10000002a(1/20)--1000000 a(1/10)=-1000000 a=-10000000--10power7

acceleration of bullet is-10power7or -10000000

by using F=ma F=0.01(10000000) F=1/100(10000000) F=-10000ON

there fore resistive force of bullet -10000ON

b)by using a=v-u/t -10000000-0-1000/t -10000000=-1000/t -10000=t

or t=-10"seconds

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