a bullet of 10 g strikes a sandbag at speed od 10 ms and gets embedded after travelling 5 cm calculat , the resistive force exterted by the the sand on the bullet
Answers
Answered by
1
Explanation:
v^2 =u^2+2as
0=(10^3)^2+2×a×(5×10^−2)
a=−10^7m/s^2
v=u+at
0=10^3−10^7×t
t=10^−4 s
Similar questions