Question

A bullet of 10 gram strikes a sandbag at a speed of 10^3 metre per second and get enbedded after travelling 5 centimetre calculate the resistance force exerted by the sand on the bullet the time taken by the bullet to come to rest

Answer 1

According to work energy theorem
F×d= change in kinetic energy
F× 0.05= 1/2×0.01 ×10^6
F= 10^4 N

Answer 2

Answer:

Explanation:

mass of bullet is 10g=1/100 kg

it is fired with speed 103m/s which is u(initial speed)

its gets embedded and stops hence v=0

the distance it travelled is 5cm=1/20m which is S

using 3rd equation of motion

2aS=v²-u²

2a1/20=0-(103)²

a/10=-(103)²

a=-10(103)²  negative sign shows that is decelerated

now we know that F=ma

F=1/100×10(103)²

F=(103)²/10

F=1060.9N

hence the force by which the bullet resisited and stopped is 1060.9N