A bullet of 10 gram strikes a sandbag at a speed of 10 power 3 and gets embedded after travelling 5 cm calculate the resistive force exerted by 7:00 on the bullet.
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Answer:
v
2
=u
2
+2as
0 = (10^3)^2 + 2 \times a \times (5 \times 10^{-2})0=(10
3
)
2
+2×a×(5×10
−2
)
a=-10^7\ m/s^2a=−10
7
m/s
2
v = u + atv=u+at
0 = 10^3 -10^7 \times t0=10
3 −10 7×t
t = 10^{-4}\ st=10
−4 s
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