Question

A bullet of 10 gram strikes a sandbag at a speed of 10 raise to 3 M per second and gets embedded after travelling 5 cm then find the resistance force exerted by the sand on the bullet and also find the time taken by the bullet to come to arrest​

Answer 1

Answer:

the depth of bullet = 5cm = 0.05cm

mass of bullet = 10gm = 0.01 kg

now by third eqn. of motion

v^2 – u^2 = 2as0 – 1000×1000 = 2 × a ×0.05

a = –10000000 m/s^2

here -ve sign indicates that acceleration is opposite to the motion.

now

a). force = ma  = 0.01 × 10000000 = –100000 N

b). time taken by the bullet to get stopped= v = u + at=> 0 = 1000 – 100000×t 1000 = 100000 × t =>t = 0.01 sec

Answer 2

Answer:

https://app.edmentum.com/mimetex/mimetex?\fs3%20\textrm{T}_{(^{\circ}\textrm{C})}=%20\left%20(%20\textrm{T}_{(^{\circ}\textrm{F})}-32%20\right%20)\times%20\frac{5}{9}

Explanation:

hope this helps