Question

A bullet of 10 gram strikes a sandbag at a speed of 103 metre per second and gets embedded after travelling 5 cm find the resistive force exerted by the sand on the bullet and time

Answer 1

hello,
mass of bullet is 10g=1/100 kg
it is fired with speed 103m/s which is u(initial speed)
its gets embedded and stops hence v=0
the distance it travelled is 5cm=1/20m which is S
using 3rd equation of motion
2aS=v²-u²
2a1/20=0-(103)²
a/10=-(103)²
a=-10(103)²  negative sign shows that is decelerated
now we know that F=ma
F=1/100×10(103)²
F=(103)²/10
F=1060.9N
hence the force by which the bullet resisited and stopped is 1060.9N
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Answer 2

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