Question

a bullet of 10 grams strikes a sandbag at a speed of
${10}^{3} meter \: per \: seconds \:$
and gets embedded , as per travel 5 cm calculate :
1) the resistive force exerted by the sand on the bullet
2) the time taken by the bullet to come to rest
please answer to all questions​

Answer 1

Explanation:

Given :

• speed of bullet = 10³ m/s
• distance = 5cm

To find :

Time taken by the bullet to come to rest

Solution :

We know that,

v² = u²+2as

Therefore,

$0 = { ({10}^{3}) }^{2} + 2 \times a \times (5 \times {10}^{ - 2} )$

a = -10⁷ m/s²

And, v = u + at

0 = 10³ - 10⁷× t

$t \: = \: {10}^{ - 4} s$

$therefore \: the \: time \: taken \: by \: the \\ \: bullet \: to \: come \: to \: rest \: is \: {10}^{ - 4} s$