A bullet of 10g leaves a 20kg gun with a velocity 100m/s. find the velocity of recoil of the gun.
Answers
Given : From a rifle of mass 20kg, a bullet of mass 10g is fired with an initial velocity of 100m/s.
To Find : What is the initial velocity of recoil of the rifle ?
Solution:
Apply conservation of momentum
initial Momentum = (20kg + 10g) * 0 = 0 kgm/s
, a bullet of mass 10g is fired with an initial velocity of 100m/s.
=> mv = (10/1000) 100 = 1 kgm/s
a rifle of mass 20kg initial velocity of recoil of the rifle = v
=> -20v ( as recoil velocity is backward velocity hence -ve sign will be there)
0 = 1 - 20v
=> 20v = 1
=> v = 1/20 m/s
=> v = 0.05 m/s
the initial velocity of recoil of the rifle = 0.05 m/s
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A bullet of 10g leaves a 20kg gun with a velocity of 100m/s. find the velocity of recoil of the gun. Find the velocity of recoil of the gun.
Step-by-step explanation:
Given data,
Mass of bullet, m=100g
To convert into kilogram(kg)= 10/1000 ⇒m = 1/100 kg
The velocity of the bullet, v=100m/s
Mass of the gun, M=20kg
Let us consider the recoil velocity of the gun as 'V'
Before firing, the system (gun+bullet) is at rest, therefore, the initial momentum of the system =0
As the system is at rest, the initial momentum of the system = 0
Final momentum of the system = momentum of bullet + momentum of the gun ⇒ mv + MV
= 1/100 × 100 + 20V
=1 + 20V
Applying the law of conservation of momentum,
Final momentum = Initial momentum
⇒ 1 + 20V = 0
20 V = −1
V = −1/20
= −0.05m/s
Therefore, the velocity of recoil of the gun is - 0.05m/s
The negative sign shows that the direction of the recoil velocity of the gun is opposite to the direction of the velocity of the bullet.