Math, asked by mdanwarhussain23740, 4 months ago

A bullet of 10g leaves a 20kg gun with a velocity 100m/s. find the velocity of recoil of the gun. ​

Answers

Answered by amitnrw
1

Given : From a rifle of mass 20kg, a bullet of mass 10g is fired with an initial velocity of 100m/s.

To Find : What is the  initial velocity of recoil of the rifle ?

Solution:

Apply  conservation of momentum

initial Momentum = (20kg + 10g) * 0  = 0 kgm/s

, a bullet of mass 10g  is fired with an initial velocity of 100m/s.

=> mv =  (10/1000) 100  = 1  kgm/s

a rifle of mass 20kg  initial velocity of recoil of the rifle = v

=> -20v   ( as recoil velocity is backward velocity hence -ve sign will be there)

0  = 1  - 20v

=> 20v =  1  

=> v = 1/20 m/s

=> v = 0.05 m/s

 

the  initial velocity of recoil of the rifle   =   0.05  m/s

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Answered by bestwriters
0

A bullet of 10g leaves a 20kg gun with a velocity of 100m/s. find the velocity of recoil of the gun. Find the velocity of recoil of the gun.

Step-by-step explanation:

Given data,

Mass of bullet, m=100g

To convert into kilogram(kg)= 10/1000 ⇒m = 1/100 kg

The velocity of the bullet, v=100m/s

Mass of the gun, M=20kg

Let us consider the recoil velocity of the gun as 'V'

Before firing, the system (gun+bullet) is at rest, therefore, the initial momentum of the system =0

As the system is at rest, the initial momentum of the system = 0

Final momentum of the system = momentum of bullet + momentum of the gun  ⇒ mv + MV

             = 1/100 ​× 100 + 20V

              =1 + 20V

Applying the law of conservation of momentum,

Final momentum = Initial momentum

      ⇒ 1 + 20V = 0

              20 V = −1

                    V = −1/20

                   = −0.05m/s

Therefore, the velocity of recoil of the gun is - 0.05m/s

The negative sign shows that the direction of the recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

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