Question

a bullet of 20 gm is shot from a gun of 2 kg at a 100 m/s find out the recoil velocity of the gun?​

Answer 1

Mass of bullet, m=100g= 100/1000 kg= 1/10  kg

Velocity of bullet, v=100ms^−1

Mass of gun, M=20kg

Let recoil velocity of gun =V

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

=mv+MV= 1/10

×100+20V=10+20V

Applying law of conservation of momentum, Final momentum = Initial momentum

i.e., 10+20V=0

20V=−10

or V=− 10/20

=−0.5ms^−1

 

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

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