Physics, asked by salaphyking, 11 months ago

A bullet of 200 gm hits a wall with 500J kinetic Energy. if its retardation in a sack is 4000 meter persecond . Calculate its covering distance in sack. Help and explain mathematically pls <3

Answers

Answered by Hritik1011
0

Answer:

5/8m

Explanation:

final kinetic energy =0

1/2m(v²-u²) = 500

1/2*1/5*u²= 500

u² = 5000

use eqn v²-u²= 2as

0-5000 =-2*4000s

s= 5/8m


Hritik1011: m = 2oo gm = 1/5 kg, 1/2*m*v^2
Hritik1011: plss mark as brainlist
salaphyking: bro what does the (*) mean
Hritik1011: multiply
salaphyking: thanks bro <3
Hritik1011: its ok
salaphyking: 1/2m(v²-u²) how did u get this
salaphyking: which formula is this
Hritik1011: change in kinetic energy
Hritik1011: final kinetic energy -initial kinetic energy
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