A bullet of 200 gm hits a wall with 500J kinetic Energy. if its retardation in a sack is 4000 meter persecond . Calculate its covering distance in sack. Help and explain mathematically pls <3
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Answer:
5/8m
Explanation:
final kinetic energy =0
1/2m(v²-u²) = 500
1/2*1/5*u²= 500
u² = 5000
use eqn v²-u²= 2as
0-5000 =-2*4000s
s= 5/8m
Hritik1011:
m = 2oo gm = 1/5 kg, 1/2*m*v^2
plss mark as brainlist
bro what does the (*) mean
multiply
thanks bro <3
its ok
1/2m(v²-u²) how did u get this
which formula is this
change in kinetic energy
final kinetic energy -initial kinetic energy
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