Question

A bullet of 5 gram is fired from a pistol of 1.5 kg if the recoil velocity of Pistol is 1.5 metres per second find the bullet velocity of the bullet ​

Answer 1

Answer:

m1=5g= 0.005kg

m2=1.5kg

v1=1.5m/s

according to conservation of momentum,

m1v1 = m2v2

hence,

v2=(m1v1)/m2

ie,

$\frac{0.005 \times 1.5}{1.5} = 0.005m {s}^{ - 1}$