Question

A bullet of 50g strikes a target with a velocities of 600m/s It velocity reduced 150m/s after penetrating the target How much energy of bullet was used to penetrate the target​

​

Answer 1

Answer:

$Mass \: of \: bullet \: = 50g = 0.05m \\ \\ Initial \: velocity \: of \: bullet \: = u \\ = 600 \: metre \: per \: second \\ \\ Velocity \: of \: bullet \: after \: \\ penetrating \\ = v = 150 \: metre \: per \: second$

To find :-

$Energy \: of \: bullet \: used \: to \: \\ penetrate \: the \: target..$

Solution :-

$We \: know \: \: by \: conversation \: of \: \\ energy.. \\ \\ Energy \: used = loss \: in \: \\ kinetic \: Energy.. \\ \\ Energy \: used \: = k.e _{i} - k.e _{f} \\ \\ Energy \: used = \frac{1}{2} mu ^{2} - \frac{1}{2} {mv}^{2} \\ \\ Energy \: used = \frac{m}{2} ( {u}^{2} - {v}^{2} ) \\ \\ Energy \: used = \frac{0.05}{2} \times ( {600}^{2} - {150}^{2} ) \\ \\ Energy \: used = 8437.5 \: J$

Step-by-step explanation:

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Answer 2

Answer:

\begin{gathered}Mass \: of \: bullet \: = 50g = 0.05m \\ \\ Initial \: velocity \: of \: bullet \: = u \\ = 600 \: metre \: per \: second \\ \\ Velocity \: of \: bullet \: after \: \\ penetrating \\ = v = 150 \: metre \: per \: second \\ \end{gathered}

Massofbullet=50g=0.05m

Initialvelocityofbullet=u

=600metrepersecond

Velocityofbulletafter

penetrating

=v=150metrepersecond

To find :-

\begin{gathered}Energy \: of \: bullet \: used \: to \: \\ penetrate \: the \: target..\end{gathered}

Energyofbulletusedto

penetratethetarget..

Solution :-

\begin{gathered}We \: know \: \: by \: conversation \: of \: \\ energy.. \\ \\ Energy \: used = loss \: in \: \\ kinetic \: Energy.. \\ \\ Energy \: used \: = k.e _{i} - k.e _{f} \\ \\ Energy \: used = \frac{1}{2} mu ^{2} - \frac{1}{2} {mv}^{2} \\ \\ Energy \: used = \frac{m}{2} ( {u}^{2} - {v}^{2} ) \\ \\ Energy \: used = \frac{0.05}{2} \times ( {600}^{2} - {150}^{2} ) \\ \\ Energy \: used = 8437.5 \: J\end{gathered}

Weknowbyconversationof

energy..

Energyused=lossin

kineticEnergy..

Energyused=k.e

i

−k.e

f

Energyused=

2

1

mu

2

−

2

1

mv

2

Energyused=

2

m

(u

2

−v

2

)

Energyused=

2

0.05

×(600

2

−150

2

)

Energyused=8437.5J

Step-by-step explanation:

________________________

Here is your answer dear, hope it will helps you...

Have a good day...