Question

A bullet of 50g was fired from a gun of mass 4kg with initial velocity 35ms-1 calculate initial backward force acting on the gun?

Answer 1

Answer:

Momentum of bullet=m×v

=(50÷1000)*35

=0.05*35

=1.75 kg m/s

Momentum of rifle=m×v

Let the recoil velocity be 'v' m/s

Hence, momentum of rifle=4×v

According to law of conservation of momentum:

Momentum of bullet=momentum of rifle

1.75=4*v

v=1.75÷4

v=0.4375 m/s

Recoil velocity is=0.4375 m/s

If the time is given, we can find the initial backward force by multiplying mass of gun with the above calculated recoil velocity and dividing by time.

Please mark as brainliest if it helped!!!