A bullet of 5g , travelling at a speed of 100 m/s penetrates a wooden block up to 6.0 cm. Then the average force applied by the bullet on the block is-a) 417 Nb) 8333 Nc) 83.3 Nd) 0
Answers
Answered by
1
V²= u² + 2as
2as = v²- u²
2 x a x (6/100) = 0 - (100)²
12a / 100 = - 10000
a = -1000000 / 12 m/s²
This is the average retardation of the bullet
Avg force F = m a
= (5/1000) x 1000000 / 12 = 416.66 N
Approx 417 newton
So the answer is: a)417 N
Hope it helps!!
2as = v²- u²
2 x a x (6/100) = 0 - (100)²
12a / 100 = - 10000
a = -1000000 / 12 m/s²
This is the average retardation of the bullet
Avg force F = m a
= (5/1000) x 1000000 / 12 = 416.66 N
Approx 417 newton
So the answer is: a)417 N
Hope it helps!!
Answered by
0
Answer:
Correct option is (a) 417 N
Explanation:
a = (v^2 - u^2) / (2S)
a = -u^2 / (2S)
a = -100^2 / (2 * 0.06)
a = -83333 m/s^2
Magnitude of retardation = -a = 83333 m/s^2
F = m(-a)
F = 0.005 * 83333
F = 416.65 N
F ≈ 417 N
Correct option is (a) 417 N
Similar questions