Question

A bullet of mass 0.001 kg is fired from a gun 2kg If the Velocity of the bullet is 72/0km ph ,calculate recoil of gun ​

Answer 1

from momentum conservation m1u1+m2u2=m1v1+m2v2 and when bullet is not fire then gun and bullet inrest so m1v1= -m2v2 here m1 is 2kg v1 =? and m2 is 0.001 v2 is 72km/h(20m/s) so 2×v1= - 0.001×20,,, 2×v2 = -0.02 then v1 is -0.02/2 means v1 is -0.01 m/sec

Answer 2

Question

A bullet of mass 0.01 kg is fired from a gun weighing 5.0 kg. If the initial speed of the bullet is 250 m/s, calculate the speed with which the gun recoils.

Answer is given in the picture !!