a bullet of mass 0.01 kg is fired from a gun weighting 5 kg. If the initial speed of bullet is 250m/s,calculate the with which the gun recoils
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Answer:
125000m/s
Explanation:
let mass of bullet=m
mass of gun=M
speed of bullet=v
than,speed which the gun recoil (u) =
(M×v)/m
u=(5×250)/0.01= 1250/0.01
u=1250×100/1
u=125000m/s
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