Question

A bullet of mass 0.01 kg is fired with a velocity of 100 m/s from a rifle of mass 20 kg. The recoil velocity of the rifle is *​

Answer 1

Answer:

M1=0.01 kg

V1=100m/s

M2=20kg

V2=?

M1V1=M2V2

0.01*100=20*V2

1=20*V2

V2=1/20

V2=0.05

Hope this helps you

Answer 2

Given:

A bullet of mass 0.01 kg is fired with a velocity of 100 m/s from a rifle of mass 20 kg.

To find:

Recoil velocity of rifle ?

Calculation:

Applying CONSERVATION OF LINEAR MOMENTUM principle:

• Let final velocity of gun be v_(2).

• Initial velocity of both gun and bullet is zero.

$\sf \therefore\: m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$

$\sf \implies\: 0 + 0 = (0.1 \times 100) + 20v_{2}$

$\sf \implies\: 20v_{2} = - 10$

$\sf \implies\: v_{2} = - 0.5 \: m {s}^{ - 1}$

So, recoil velocity of gun is 0.5 m/s.

• Please note that '-' sign denotes that recoil velocity is opposite to the direction of bullet velocity.