A bullet of mass 0.01 kg moving horizontally strikes a block of 2 kg what is the final velocity of the bullet
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need to give the sticking velocity of the bullet check the question otherwise what would one solve conclusion question incomplete check it out
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Explanation:
The question can be answered in any conservation method
I use conservation of momentum
Mass of bullet = 10g = 10⁻² kg ; mass of block = 2kg
speed of bullet = 400m/s ; height raised = 0.1 m
for the block
mgh = 1/2mv² ------- v =√(2gh) = 1.4 m/s
mv = m1v1 + m2v2
If v₂ is the final speed , v₂ = (10⁻² x 400) - (2 x 1.4) / 10⁻2
= (4 - 2.8) x 10²
= 120 m/s
Hope you understand
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