Question

A bullet of mass 0.02 kg is fired from a gun weighing 7.5 kg if the initial velocity of bullet is 200 m/s. Calculate the speed with which the gun recoils.

Answer 1

$\boxed{\bf{ \blue{\bigstar Find \longrightarrow }}}$

• Speed with which the gun recoils

$\boxed{\bf{ \red{\bigstar Given \longrightarrow }}}$

• Mass of bullet=0.02 kg
• Mass of gun=7.5 kg
• Speed of bullet=200 m/s

$\boxed{\bf{ \pink{\bigstar Formula \ used \longrightarrow }}}$

$\boxed{\bf{MV=mv}}$

where,

M= mass of bullet

V= velocity of bullet

m= mass of gun

v= velocity of gun

$\boxed{\bf{ \orange{\bigstar SoLution \longrightarrow }}}$

Using Law of Conservation of momentum

MV=mv

put the given value in the formula we get,

$\bf{0.02 \times 200 = 7.5 \times v}$

$\bf {v=\dfrac{2\times 2}{7.5} }$

$\bf{v= \dfrac{4}{7.5} }$

$\bf { v= 0.53 }$

$\small{\underline{\rm{\green{\therefore Speed \ with \ which\ gun \ is \ recoils \ is \ 0.53m/s}}}}$

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Answer 2

Answer:

\boxed{\bf{ \blue{\bigstar Find \longrightarrow }}}★Find⟶

Speed with which the gun recoils

\boxed{\bf{ \red{\bigstar Given \longrightarrow }}}★Given⟶

Mass of bullet=0.02 kg

Mass of gun=7.5 kg

Speed of bullet=200 m/s

\boxed{\bf{ \pink{\bigstar Formula \ used \longrightarrow }}}★Formula used⟶

\boxed{\bf{MV=mv}}MV=mv

where,

M= mass of bullet

V= velocity of bullet

m= mass of gun

v= velocity of gun

\boxed{\bf{ \orange{\bigstar SoLution \longrightarrow }}}★SoLution⟶

Using Law of Conservation of momentum

MV=mv

put the given value in the formula we get,

\bf{0.02 \times 200 = 7.5 \times v}0.02×200=7.5×v

\bf {v=\dfrac{2\times 2}{7.5} }v=7.52×2

\bf{v= \dfrac{4}{7.5} }v=7.54

\bf { v= 0.53 }v=0.53

\small{\underline{\rm{\green{\therefore Speed \ with \ which\ gun \ is \ recoils \ is \ 0.53m/s}}}}∴Speed with which gun is recoils is 0.53m/s

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