Question

A bullet of mass 0.02kg is fired by a gun of mass 100 kg. If the speed of the bullet is 80m/s .Calculate the recoil speed of the gun

Answer 1

Answer:

0.016 m/s

Explanation:

according to law of conservation of momentum mass of bullet×velocity of bullet is equal to mass of gun×recoil velocity of gun

Answer 2

The recoil speed of the gun is 0.016 m/s.

Explanation:

It is given that,

Mass of the bullet, m = 0.02 kg

Mass of the gun, M = 100 kg

Speed of the bullet, v = 80 m/s

Let V is the recoil speed of the gun. The momentum of the system remains constant. It can be calculated using the conservation of momentum as :

$mv=MV$

V is the recoil speed of the gun

$V=\dfrac{mv}{M}$

$V=\dfrac{0.02\times 80}{100}$

V = 0.016 m/s

So, the recoil speed of the gun is 0.016 m/s. hence, this is the required solution.

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Conservation of momentum

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