a bullet of mass 0.02kg is fixed by a given of mass 20 kg .If the speed of the bullet is 150m/s . calculate the recall speed of the given
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according to rule of moment conservation
m1v1=m2v2 -------------------eq1
if the velocity of the 20kg mass is zero than
moment befor hitting the object =m1v1
= 0.02kg*150m/s -------------eq2
lets assume the return speed of the bullet is Vr
than moment after hitting the object= m2V2
= 0.02kg*Vr m/s -------------eq3
using eq 1,2,3
0.02kg*150m/s=0.02kg*Vr m/s
Vr= 150 m/s
means return speed of the bullet is 150 m/s
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