Question

A bullet of mass 0.02kg moving at a speed of 10m/s. It can penetrate 10cm of wooden block and comes to rest .if the thickness of the target would be 6cm only find the K.E of the bullet when it comes out

Answer 1

Answer:

mass of the bullet, m = 0.02 kg 

Initial speed of the bullet, u = 10 m/s 

Final speed of the bullet, v = 0 m/s 

Penetration, x = 10 cm = 0.10 m 

Using the Newton’s law of motion, we get 

v^2 = u^2 – 2ax

or, 0 = 100 – 2a*0.1 

or, a = 100/0.2 

or, a = 500 m/s^2 

Thus, retardation a = 500 m/s^2 

Now, when thickness of the wooden block x = 6 cm = 0.06 m 

v^2 = u^2 – 2ax 

or, v^2 = 100 – 2*500*0.06 

or, v^2 = 40 

or, v = 6.325 m/s 

Kinetic energy of the bullet, KE = ½ mv^2 

= ½*0.02*40 = 0.4 J 

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Answer 2

Answer:

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