Question

A bullet of mass 0.02kg moving with a speed of 100ms-1 enters a heavy wooden block and is stopped after a distance of 50cm What is the average resistive force exerted by the block on the the bullet
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Answer 1

Explanation:

The retardation of the bullet is given as,

a=−2su2

=−2×60×10−290×90

=−6750m/s2

The retarding force is given as,

F=−ma

=0.04×6750

=270N

Thus, the average resistive force is 270N.