Question

A bullet of mass 0.03 kg enters a block of wood With a Vdiqcity of 600 m/s and penetrates to
a depth of 0.2 m. Calculate the average forge of the wood to the penetration of the bullet.

Answer 1

Answer:

change of momentum = .03*600 = 18

average speed = 300

time = .2/300

Force = change of momentum/change of time

= 18 *300/.2 Newtons

= 90*300

=27,000 agree