a bullet of mass 0.03kg moving with a speed of 48 m / sec penetrates 12 cm into a fixed block of wood . calculate the work done by the bullet and the force exerted by the wood on the bullet .
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formula to be used :- v2 = u2-2as;
v = final speed = 0
u = initial speed = 600 m/s
a = retardation;
s = distance travelled by bullet in wooden block = 0.6 m
retardation = (600×600)/(2×0.6);
resistive force = mass of bullet × retardation = 0.03 ×(600×600)/(2×0.6) = 9000 N..
for work done
use w = f.S
so w = 9000 ×0.6= 540joule
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v = final speed = 0
u = initial speed = 600 m/s
a = retardation;
s = distance travelled by bullet in wooden block = 0.6 m
retardation = (600×600)/(2×0.6);
resistive force = mass of bullet × retardation = 0.03 ×(600×600)/(2×0.6) = 9000 N..
for work done
use w = f.S
so w = 9000 ×0.6= 540joule
please mark this answer as brainliest and follow me too
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