Physics, asked by shabinaanjum2003, 1 year ago

A bullet of mass 0.04 kg fired with a speed of 802 m/s hit a block of 16kg which is at rest. The loss in kinetic energy if common speed of block and bullet is 2 m/s is:
A) 1283.2J
B) 128.32J
C) 12.832J
D) 12832J

Answers

Answered by Princeashishkumar01
6

Answer:12832

Explanation:

Loss in kE is

KE(initial)—kE(final)

1/2*0.02*802(squar)—1/2*16.04*2(squar)

12864.08-32.08

12832 J

Note commen velocity is given i. E

After collision both bullet+block moves together so I have added masses of both and took as 16.04

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