Question

A bullet of mass 0.04 kg moving with a speed of 9 meter per second
enters a having wooden block and is stopped after a distance of 60cm . The average resistive force exerted by the block is​

Answer 1

Answer:

metering centimetres akshdhhfhfg

Answer 2

Answer:

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v

2

−u

2

a=−

2S

u

2

a=−

2×60×10

−2

90×90

=−6750m/s

2

The resistive force, f=ma

f=−0.04×67.5

f=−270N