A bullet of mass 0.04 kg moving with a speed of 90 M per square interviewed and lock uninstall after transferring and distance of 6 m what is the average resistance force exerted by the block on the bullet
Anonymous:
90 m per square????
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F*S=1/2 mv^2
F =0.04*90^2/2*6
F. =27N
resistance force applied by the block is 27N
F =0.04*90^2/2*6
F. =27N
resistance force applied by the block is 27N
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