Question

A bullet of mass 0.04 kg moving with a speed of 90 m/s enters a heavy wooden block and stops after a distance of 0.6 m. What is the average resistance force exerted by the block on the bullet?​

Answer 1

Answer:

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Answer 2

Answer:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v^2 −u^2

a=−  u^2 /2S

a=−90×90  /2×60×10^−2

=−6750m/s^2

The resistive force, f=ma

f=−0.04×67.5

f=−270N

hope it helps