Question

A bullet of mass 0.04 kg moving with speed of 19 metre per second enters a heavy wooden block and stopped at a distance of 60 cm. what is the average resistive force exerted by the block on the bullet?​

Answer 1

Answer:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v

2

−u

2

a=−

2S

u

2

a=−

2×60×10

−2

90×90

=−6750m/s

2

The resistive force, f=ma

f=−0.04×67.5

f=−270N