a bullet of mass 0.04 kg moving with speed of 20m/s enter a heavy wooden block and is stopped after a distance of 60cm. what is average resistive force exerted by block on bullet
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Mass of bullet 0.04
U of bullet 20
V is 0
a will be v^2-U^2/2s
=-20/6
F = MA
F= 0.04*-20/6
F=-4.8N
U of bullet 20
V is 0
a will be v^2-U^2/2s
=-20/6
F = MA
F= 0.04*-20/6
F=-4.8N
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