Question

A bullet of mass 0.04 kilogram moving with a speed of 90 m per second enters into a heavy wooden block and stopped after a distance of 60cm what is the average resistance force exerted by the block on the bullet

Answer 1

mass of bullet=4/100 kg
u=90m/s
v=0
s=60cm=6/10m
v^2-u^2=2as
0^2-90^2=2*a*6/10
0-8100=12/10*a
a=-8100*10/12
a=-6750m/s
f=ma
f=4/100*(-6750)
f=270N