Question

A Bullet of mass 0.04kg moving with a speed of 90m/s enters a heavy wooden block and is stopped after a distance of 60cm. what is the average resistive force exerted by the block
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Answer 1

Hey, The answer is 270.

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First, we have to find it's acceleration

v^2 = u^2 + 2 as

v = 0; u = 90 m/s ; s = 0.6 m (60 cm)

0 = (90)^2 + 2 × a × 0.6

0 = 8100 + 1.2 a

-8100 = 1.2 a

a = - 8100/1.2 = -6750 m/s^2

average resistive force exerted by the block on bullet =?

= mass × acceleration

= 0.04 kg × -6750 m/s^2

= 270 N (avg. only)

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Hope this helps!

Answer 2

Answer:

270

Explanation:

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