A bullet of mass 0.05 kg enters a block of wood of length 50 cm at 400 m/s. It emerges at 100m/s. Find (a) change in the KE of the bullet, (b) the force exerted by the wood on the bullet( Plz give full solution as class 11 )
Answers
Answer:
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
Explanation:
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
bro please type in Hindi so I understand if you type in Hindi because I don't understand English so please bro sorry for this
Answer:
Mass of the bullet is mb = 50 gm = 0.05 Kg Initial velocity of bullet ub = 100 m/s Final velocity is vb = 0 m/s (1) Initial momentum of bullet pi = ...